No guarantee for correctness: (generated Nov. 2008)

http://www.stanford.edu/~huangty/Solution2006.pdf

MCQ

4) [b] False - The receive is *not* used to control *congestion on the network*

6) [b] , [d]

8) [a] , [d] 

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LONGER QUESTIONS 

11) (a) Consider the 32-bit seq-no wrap around  and the Maximum Segment Lifetime (MSL).

We need the time for the wrap around < MSL.

Time Until Wrap Around (numbers from http://www.scs.stanford.edu/09au-cs144/notes/l2.pdf )

2^32 / (MSL = 2mins) = Max Bandwidth we will be comfortable with

Bandwidth

T1 (1.5 Mbps) 6.4 hours

Ethernet (10 Mbps)  57 minutes

T3 (45 Mbps)   13 minutes 

FDDI (100 Mbps)  6 minutes 

STS-3 (155 Mbps)  4 minutes 

STS-12 (622 Mbps)  55 seconds 

STS-24 (1.2 Gbps)  28 seconds

11) (b) The window size helps to determine how well the network is utilized. If latency and bandwidth are too high, we need a greater window size to utilize the network.

13) (c) Security, Routing information (esp. for Wireless). We couldn't come up with a 3rd application where end-to-end is no longer applied.